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5x^2+25x-15000=0
a = 5; b = 25; c = -15000;
Δ = b2-4ac
Δ = 252-4·5·(-15000)
Δ = 300625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300625}=\sqrt{625*481}=\sqrt{625}*\sqrt{481}=25\sqrt{481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25\sqrt{481}}{2*5}=\frac{-25-25\sqrt{481}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25\sqrt{481}}{2*5}=\frac{-25+25\sqrt{481}}{10} $
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